(Paper) HCL Placement Paper and Pattern (Technical)

PAPER: HCL Placement Paper and Pattern (Technical)

Section I: computer awareness 

Section II: Simple C- language 

Section III: On pointers & structures and C++, JAVA(only 1 on this) 

Section IV: Analytical 

1. Which of the following involves context switch,

(a) system call (b) privileged instruction) floating point exception) all the above (e) none of the above

Ans: (a)

2. In OST, terminal emulation is done in

(a) sessions layer b) application layer c) presentation layer (d) transport layer

Ans: (b)

3. For a 25MHz processor , what is the time taken by the instruction which needs 3 clock cycles,

(a)120 nano secs(b)120 micro secs(c)75 nano secs(d)75 micro secs ans a

4. For 1 MB memory, the number of address lines required,

(a)11 (b)16 (c)20(d) 24

Ans. (c)

5. Semaphore is used for

(a) synchronization b) dead-lock avoidance (c) box (d) none

Ans. (a)

6. Parity error checking is used for.........?

Ans: a odd numbers of errors

7. Address on internet are (Internet IP address is unique for..)

a) unique for particular domain

b) unique for a particular sub-node list

c) unique countrywide

d) unique in a network area

Ans: b has to be unique in the sub network

8. one ans is c Volatile modifier

9. OLE is used in
a) inter connection in Unix

b) interconnection in WINDOWS

c) interconnection in WINDOWS NT

ans c(check)

10. Convert a given HEX number to OCTAL

11. Macros and function are related in what aspect?

(a) recursion

(b) varying no of arguments

(c) hypo checking

(d) type declaration

Ans d or a (check)

12.Preprocessor does not do which one of the following

(a) macro

(b) conditional complication

(c) in type checking

(d) including load file

Ans. (c)

13. Piggy backing is a technique for

a) Flow control

b) Sequence

c) Acknowledgement

d) retransmission

Ans. (c)

14. In signed magnitude notation what is the minimum

value that can be represented with 8 bits

(a) -128

(b) -255

(c) -127

(d) 0

Ans a

15. There is an employer table with key fields as employer number data in every n'th row are needed for a simple following queries will get required results.

(a) select A employee number from employee A , w here exists from employee B where A employee no. = B employee having (count(*) mod n)=0

(b) select employee number from employe A, employe B where A employe number=B employ number group by employee number having(count(*) mod n=0 )

(c) both (a) & (b)

(d) none of the above

15. Type duplicates of a row in a table customer with on uniform key field customer number you can see

a) delete from customer where customer number exists (select distinct customer number from customer having count )

b) delete customer a where customer number in b rowid 

c) delete customer a where customer number in( select customer number from customer a, customer b )

d) none of the above

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